Irrational equations 64^1/3 how to simplify?

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asked Jan 11, 2017 213k views

2 Answers

Mallendeo · Answer 1 · 2017-01-18T13:46:20+0000

For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.

So, 64^(1/3) is the third root of 64, which is equal to 4.

Irrational equations 64^1/3 how to simplify?

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