Question

PLEASE HELP with detailed explanation of the formulas**

A 10.0-gram sample of H2O(l) at 23.0°C absorbs 209 joules of heat. What is the final temperature of the H2O(l) sample?

(1) 5.0°C
(2) 18.0°C
(3) 28.0°C
(4) 50.0°C

Answer 1

Q= m*c*ΔT
⇒ 209 J= 10.0 g* 4.18 J/(g*C)* (x- 23.0 C)
⇒ ...
⇒ x= 28.0 C

(3) 28.0°C is the correct answer.

Hope this helps~