Question

How can I anwser this one? ?
4x2+16x=0

Answer 1

Divide each side of the equation by 4 :

x² + 4x = 0

Factor the left side:

x (x + 4) = 0

This equation is true if x=0 or if x=-4 , so those are the two solutions.

Answer 2

`4x^2+16x=0`


`(4x^2+16x)/(4) =(0)/(4)`


`x^2+4x=0`


`x(x+4)=0`


`x=0`


`x+4=0`


`x+4-4=0-4`


`x=-4`



`x=-4,0`