Question

The area of the garden is 160 meter squared.Suppose the length of the garden is 3m more than twice its width.What is the length of the garden?

Answer 1

`w-width\\\\2w+3-length\\\\160m^2-area\ of\ the\ garden\\\\w\time(2w+3)-area\ of\ the\ garden\\\\w(2w+3)=160\\\\2w^2+3w-160=0`


`a=2;\ b=3;\ c=-160\\\\\Delta=b^2-4ac\to\Delta=3^2-4\cdot2\cdot(-160)=9+1240=1249\\\\w_1=(-b-\sqrt\Delta)/(2a);\ w_2=(-b+\sqrt\Delta)/(2a)\\\\\sqrt\Delta=√(1249)\approx35.34\\\\w_1=(-3-35.34)/(2\cdot2) < 0;\ w_2=(-3+35.34)/(2\cdot2)=(32.34)/(4)=8.085\ (m)\\\\length\approx2\cdot8.085+3=19.17\ (m)`