Question

The two points (-2,4) and (4,2) are the endpoints of the diameter of a circle. What is the equation of this circle in standard form?

Answer 1

`Center\ of\ the\ circle\ is\ the\ midpoint\ AB\ where\ A(-2;\ 4)\ \&\ B(4;\ 2)\\\\center:O\left((-2+4)/(2);\ (4+2)/(2)\right)\to O(1;\ 3)\\\\Radius\ of\ the\ circle\ is\ distance\ O\ to\ A:\\\\r=|OA|=√((-2-1)^2+(4-3)^2)=√(9+1)=√(10)\\\\Equation\ of\ a\ circle:\\\\(x-a)^2+(y-b)^2=r^2\ whete\ center\ is\ (a;\ b)\ and\ radius\ is\ r.\\\\Equation\ of\ this\ circle:\\\\(x-1)^2+(y-3)^2=(√(10))^2\\\\(x-1)^2+(y-3)^2=10`