Question

Use the functions f(x) = 3x – 4 and g(x) = x2 – 2 to answer the following questions. Complete the tables.



x f(x)

–3–1 0 2 5

x g(x) –3–1 0 2 5

For what value of the what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) {–3, –1, 0, 2, 5} does f(x) = g(x)? Answer:
















consider the relation {(–4, 3), (–1, 0), (0, –2), (2, 1), (4, 3)}. Graph the relation.
State the domain of the relation. State the range of the relation. Is the relation a function? How do you know? Answer:











2. graph the function f(x) = |x + 2|.


Answer:






consider the following expression. Rewrite the expression so that the first denominator is in factored form. Determine the LCD. (Write it in factored form.) Rewrite the expression so that both fractions are written with the LCD. Subtract and simplify.

Answer:

Answer 1

-11 and 0 for EDGE2020

f(4)= -11

If g(x)=2, x= 0

Explanation:

Answer 2

`1)\\f(x)=3x-4\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ f(x)\ |\ \ -13\ \ |\ \ -7\ \ |\ -4\ \ |\ \ \ 2\ \ \ |\ \ \ 11\ \ |\\\\f(-3)=3\cdot(-3)-4=-9-4=-13\\f(-1)=3\cdot(-1)-4=-3-4=-7\\f(0)=3\cdot0-4=0-4=-4\\f(2)=3\cdot2-4=6-4=2\\f(5)=3\cdot5-4=15-4=11`


`g(x)=x^2-2\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ g(x)\ |\ \ \ \ \ 7\ \ \ \ |\ \ -1\ \ \ |\ -2\ \ |\ \ \ 2\ \ |\ \ \ 23\ \ |\\\\g(-3)=(-3)^2-2=9-2=7\\g(-1)=(-1)^2-2=1-2=-1\\g(0)=0^2-2=0-2=-2\\g(2)=2^2-2=4-2=2\\g(5)=5^2-2=25-2=23\\\\f(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x=2,\ \ \ \ because\ \ \ \ f(2)=2\ \ \ and\ \ \ g(2)=2`


`2)\\the\ relation:\ \{(-4, 3), (-1, 0), (0, -2), (2,1), (4, 3)\}.\\\\the\ domain:\ D=\{-4,-1,0,2,4\}\\the\ range:\ R=\{3,0,-2,1\}\\\\This\ relation\ is\ the\ function,\ because\ \ each\ number\\ of\ the\ domain\ D\ has\ exactly\ one\ value\ in\ the\ range\ R.`


`3)\\f(x)=|x+2|\\\\|x+2|= \left \{ {\big{x+2\ \ \ \ \ if\ \ \ x \geq -2} \atop \big{-x-2\ \ \ if\ \ \ x<-2}} \right.`