5 consecutive intergers whose sum is 195

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asked Mar 28, 2016 52.0k views

1 Answer

Benn Malengier · Answer 1 · 2016-04-01T19:45:03+0000

x + (x+1) + (x+2) + (x+3) + (x+4) = 195

5x + 10 = 195

5(x+2) = 195

x + 2 = 39

x = 37

The 5 consecutive integers whose sum is 195 are 37, 38, 39, 40, 41.

5 consecutive intergers whose sum is 195

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