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How do I solve n^2-5n-14=0 by factoring

How do I solve n^2-5n-14=0 by factoring
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How do I solve n^2-5n-14=0 by factoring

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User Allait
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2 Answers

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n^2-5n-14=0 \\ n^2-7n+2n-14=0\\ n(n-7)+2(n-7)=0\\ (n+2)(n-7)=0\\ n=-2 \vee n=7
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User Mind Peace
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(N-7)(n+2)=0 as you'd get n^2-7n+2n-14 then just simplify. Then it would be n=-2 or 7
answered
User Sherwin Zadeh
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