Question

What's the vertex form of y=6x^2-12x+1

Answer 1

`The\ vertex\ form\ of\ y=ax^2+bx+c:y=a(x-h)^2+k\\\\where:h=(-b)/(2a)\ and\ k=(-(b^2-4ac))/(4a)\\-------------------------------\\y=6x^2-12x+1\to a=6;\ b=-12;\ c=1`


`h=(-(-12))/(2\cdot6)=(12)/(12)=1\\\\k=(-[(-12)^2-4(6)(1))/(4(6))=(-(144-24))/(24)=(-120)/(24)=-5\\\\vertex:(1-5)`


`the\ vertex\ form:\\\boxed{y=6(x-1)^2-5}`