What is the standard form of y=(x-3)^2+53

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asked Mar 1, 2016 156k views

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Gutenmorgenuhu · Answer 1 · 2016-03-06T21:29:18+0000

y = (x - 3)² + 53
y = (x - 3)(x - 3) + 53
y = (x(x - 3) - 3(x - 3)) + 53
y = (x(x) - x(3) - 3(x) + 3(3)) + 53
y = x² - 3x - 3x + 9 + 53
y = x² - 6x + 62

What is the standard form of y=(x-3)^2+53

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