Question

If y varies inversely as x and y is 1.5 when x is 8, what is y when x is 2

Answer 1

`y=(k)/(x)\\\\ 1.5=(k)/(8)\\ k=12\\\\ y=(12)/(2)\\ \boxed{y=6}`

Answer 2

Inverse variation states:

If y varies inversely as x i.,e

`y \propto (1)/(x)`

then the equation is in the form of:

`y = (k)/(x)`......[1] , where k is the constant of variation

As per the statement:

y is 1.5 when x is 8

Solve for k:

Substitute the given value in [1] we have;

`1.5 = (k)/(8)`

Multiply both sides by 8 we have;

12 = k

or

k = 12

Then, the equation become:

`y = (12)/(x)`

We have to find y when x is 2.

then;

`y = (12)/(2)`

Simplify:

y = 6

Therefore, the value of y is, 6