Question

List the partial products of 42 x 28

Answer 1

42 × 48

(40 + 2) × (40 + 8)

40 × (40 + 2) = (40 × 40) + (40 × 2) = 1600 + 80 = 1680
8 × (40 + 2) = (40 × 8) + (2 × 8) = 320 + 16 = 336

Then 1680 + 336 = 2016

Answer 2

Solution: The partial products of
`42*28` are 800, 320, 40, 16 and the value of
`42*28` is 1176.

Step-by-step explanation:

To find the partial product of two numbers, first we write the both numbers as the sum of place values of the digits. Multiply each the place value of first number with the place value of second number.

`42*28`

`(40+2)*(20+8)`

`40* 20+40* 8+2* 20+2* 8`

Multiply each pair individually.

`40* 20=800`

`40* 8=320`

`2* 20=40`

`2* 8=16`

The above values are partial product.

`800+320+40+16=1176`

Therefore, the partial products of
`42*28` are 800, 320, 40, 16 and the value of
`42*28` is 1176.