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(10y^3+20y^2+55y)/5y

(10y^3+20y^2+55y)/5y
asked 143k views
4 votes
(10y^3+20y^2+55y)/5y

asked
User Sharmile Murugaraj
by
7.5k points

2 Answers

3 votes

Answer:

2y^2+4y+11

Explanation:

(10y^3+20y^2+55y)/5y-example-1
answered
User Antyrat
by
8.0k points
3 votes
( 10y^3 + 20y^2 +55y ) / 5y
= 2y^2 + 4y +11

And then depending on if the equation is set to zero in the problem, just factor or use the quadratic formula on the quadratic equation that is left.
answered
User Hao Luo
by
8.8k points
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