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Which value of c makes y^2+8y+c a perfect square
A. 4 B.16 C.64 D.8

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User Eddy Ed
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1 Answer

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y^2+8y+c \\ \\ c=((b)/(2))^2=((8)/(2))^2=4^2 = 16 \\ \\y^2+8y+16 = (y+4)^2 \\ \\Answer : \ B. \ \ 16




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User Jacob Lee
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