asked 102k views
5 votes
How do I convert

3
x^(2) - 20x - 7 = 0

into the form it was before distribution:

( ) ( ) = 0

1 Answer

4 votes

3x^2-20x-7=0\\ 3x^2+x-21x-7=0\\ x(3x+1)-7(3x+1)=0\\ (x-7)(3x+1)=0\\ x=7 \vee x=-(1)/(3)
answered
User Peter Staranchuk
by
8.2k points

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