Find two consecutive numbers with a product of 121

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asked Feb 10, 2015 111k views

1 Answer

Rae Burawes · Answer 1 · 2015-02-14T05:21:12+0000

One number: x
Its consecutive: x + 1

Product:

x(x+1)=121
x² + x - 121 = 0

Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485

As square root of 485 is not integer, do not exist two consecutive numbers with product of 121

Find two consecutive numbers with a product of 121

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