Question

A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?

Answer 1

\frac { 104 }{ 9 } \pi " or 11.56

Explanation:

Answer 2

The circumference of a circle is:

Radius = r, Diameter = d, C = Circumference

C=2πr (as 2r=d)

C=πd

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If the radius of the circle is 26" then its diameter must be 52".

This means that the bicycle wheel has a circumference of 52π".

I'm going to divide 52π" into 360 parts (because a circle is made up of 360 degrees). I'll then multiply this value by 80 to give you an answer.


`\frac { 52\pi }{ 360 } * 80=\frac { 104 }{ 9 } \pi`

Answer:


`\frac { 104 }{ 9 } \pi`