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The decomposition of baking soda (NaHCO3) is given in this reaction: 2NaHCO3 → Na2CO3 + H2O + CO2 If 8 moles of baking soda decompose, how many moles of Na2CO3 are produced? 1 2…

The decomposition of baking soda (NaHCO3) is given in this reaction: 2NaHCO3 → Na2CO3 + H2O + CO2 If 8 moles of baking soda decompose, how many moles of Na2CO3 are produced? 1 2…
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The decomposition of baking soda (NaHCO3) is given in this reaction: 2NaHCO3 → Na2CO3 + H2O + CO2 If 8 moles of baking soda decompose, how many moles of Na2CO3 are produced? 1 2 4 8

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User Chris Gomez
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4 moles of Na2CO3

2 NaHCO3= Na2CO3+H2O+CO2

8mol NaHCO3* 1mol Na2CO3/2mol NaHCO3 = 4mol Na2CO3
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User MillerMedia
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