Question

Sylvanite is a mineral that contains 28.0% \% gold by mass. How much sylvanite would you need to dig up to obtain 34.0g g of gold?

Answer 1

Since it is said the 1g of mineral contains 28% of gold which is equivalent to .28g of gold. Thus, .28 gram of Gold = 100 grams of Minerals
=> 1g of Gold = 100/28 grams of Minerals
=> 34grams of gold = 100/28 * 34 g of Minerals
=> 34 grams of gold = 952 grams of Minerals
Therefore, it needs 952 grams of Sylvanite minerals in order to have 34 grams of Gold.