Question

Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)? HELP ME PLEASE!!

Answer Choices:


A.) (x - 1)2 + (y - 1)2 = 17


B.) (x + 5)2 + y2 = 17
C.) (x + 5)2 + y2 = 24
D.) (x - 5)2 + y2 = 17

Answer 1

a) first we will calculate the distance between center and given point because this is the radius of circle:


`d=√((1-5)^2+(1-0)^2)\\ \\ d=√((-4)^2+1)=√(17)`

b) Now we will write the equation of the circle:


`\boxed{\boxed{(x-5)^2+y^2=17}}`