Question

One of the factors of g2 − 28g + 196 is a. g-7 b. g-14 c. g+14 d. g+7

Answer 1

We can use this formula:


`\sf{x^2-2xy+y^2 =(x-y)(x-y)=(x-y)^(2)}`


`g^2 - 28g + 196 \to (g)^2 - 2(14)(g) + (14)^2`

that means:


`x = g, y = 14`

So plugging that into the formula, you get:


`g^2 - 28g + 196= (g-14)(g-14)= (g-14)^2`

Answer 2

`g^(2)-28g+196=g^(2)-14g-14g+196=g(g-14)-14(g-14)= \\ \\ (g-14)(g-14)=(g-14)^(2)`

P.S :>


`(a-b)^(2)=a^(2)-2ab+b^(2)`

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