Question

17. Solve the equation using square roots. x^2 + 5 = 41 a.+-36 b.no real number solutions c.6 d.+-6

Answer 1

`x^(2)+5=41 \\ \\ x^(2)-36=0 \\ \\ (x-6)(x+6)=0 \\ \\ x-6=0 \ \vee \ x+6=0 \\ \\ x=6 \ \vee \ x=-6 \\ \\ x\in \lbrace -6,6 \rbrace`

Answer 2

solve your equation step-by-step.

x^2+5=41

Subtract 5 from both sides.

x^2+5−5=41−5

x^2=36

Take square root.

x=±√36

x=6

or

x=−6

So your answer suppose to be C and D.
But if you were to put only one answer in the answering box, then just say C)