Question

Solve this equation
aj+j-a=f+j-f²
if a is 13 and j is 13 and f is 7

Answer 1

This is what I see 13*13+13-13=7+13-7^2

13*13+13-13=7+13-49

This is clearly false.

Here is the answer if you were techincally trying to solve it :D

(13)(13)+13−13

=169+13−13

=182−13

=169

Answer 2

Since you're given all the variable values, we can't really "solve" the equation. However, we can plug the given values in and see if they work!

Substituting in the given values, we have:
13*13+13-13=7+13-49

This is equal to:
169=-29

This is clearly not true, so the given values for the variables do not solve the equation.