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What is the eighth term of the sequence 2,8,32,128

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User Gaozhidf
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1 Answer

6 votes
It's a geometric sequence.


2,8,32,128,... \\ \\ a_1=2 \\ r=(a_2)/(a_1)=(8)/(2)=4 \\ \\ a_n=a_1 * r^(n-1) \\ a_8=2 * 4^(8-1) \\ a_8=2 * 4^7 \\ a_8=2 * 16384 \\ a_8=32768

The eighth term of the sequence is 32768.
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User Sharmin
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