Question

What is the equation of a line passing through (-6, 5) and having a slope of 1/3?

Answer 1

The equation of a line:

`y=mx+b`
m - the slope, b - the y-intercept

The slope is 1/3, so the equation of the line is
`y=(1)/(3)x+b`.
Plug the values (x,y)=(-6,5) of the point into the equation:

`5=(1)/(3) * (-6)+b \\ 5=-2+b \\ 5+2=b \\ b=7 \\ \\ \boxed{y=(1)/(3)x+7}`