Question

How many mL of .1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu

a. 250 mL
b. 26.95 mL
c. 25 mL

what do you do with the amu?

Answer 1

The amu is a unit which means the mass per neutron, So the 74.55 means the mass per mole KCl. So the mole number of 2.330g KCl is 2.330/74.55=0.031 mol. The volume is 0.031/0.1250=0.248 L ≈ 250 mL. So the answer is a.