Question

a train goes forward at a speed of 1m/s for 20 seconds then it stops and goes backward at a speed of 0.5 m/s for 4 sec after both movements are completed how far is the train located from its starting point notewe are asking for the trains final location not the total distance traveled

Answer 1

1m/s*20s = 20m forward
0.5m/s backward = -0.5m/s forward
20m+(-0.5m/s*4s) = 20m-2m = 18m forward

Or it goes forward 1*20 = 20m
then goes backward 0.5*4 = 2m
20-2=18m