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The sum of a number and twice is square is 36.find the numbers?

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x+2x^2=36\\ 2x^2+x-36=0\\ 2x^2+9x-8x-36=0\\ x(2x+9)-4(2x+9)=0\\ (x-4)(2x+9)=0\\x=4 \vee x=-(9)/(2)

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