Question

Jay traveled from Miami to Jacksonville, a distance of 320 miles. He left Miami at 8:00am, stopped for lunch for 30 minutes, and stopped for two 15 minute breaks at rest areas. He arrived in Jacksonville at 2:15pm. What was his average rate of speed during his travel time? Please explain the steps to get the answer. Thanks!

Answer 1

To find the “Average Rate of Speed", we know we need the Total Distance and the Total Time. The Total Distance is 320 miles and the Total Time is 14:15 - 8:00 = 6:15 hours = 6.25 hours .So the Average Rate = 320 miles/ 6.25 hours = 51.20 mph.