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PLS HELP ASAP :DDDDDDDDDDDDDDDDDDD

PLS HELP ASAP :DDDDDDDDDDDDDDDDDDD-example-1

1 Answer

4 votes
Pythagoras in HBC :
HC=√(HB^2-BC^2)=√(20^2-12^2)=16in

Pythagoras in HDC :
HD=√(HC^2-CD^2)=√(16^2-14^2)\approx\boxed{7.7 in}

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