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1 vote
PLEASE HELP

Solve.

m^-5 = 1/32

m = ________ ?

1 Answer

4 votes

a^(-n)=(1)/(a^n)\\\\m^(-5)=(1)/(32)\iff m^5=(1)/((1)/(32))\to m^5=32\iff m=\sqrt[5]{32}\to m=2\\\\because\ 2^5=32\\\\Answer:\boxed{m=2}
answered
User Egor Lakomkin
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