Question

A rectangle has an area of 30 square units and a perimeter of 34 meters.what are the dimensions of this rectangle

Answer 1

`P=2L+2W`

`A=WL`

Therefore, if
`P=34`, and
`A=30`, then let us find the factors of 30 that could give a sum of half of the perimeter which is 34. Therefore:


`P=2*15+2*2`

`A=15*2`


`P=34`

`A=30`

Therefore, the dimensions of this rectangle are 15 and 2.