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1. What is the empirical formula for a compound containing 63.8% N and 36.2% O? a. N₂O₅ b. N₂O₃ c. NO₂ d. NO e. N2₂O

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O? a. N₂O₅ b. N₂O₃ c. NO₂ d. NO e. N2₂O
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1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?

a. N₂O₅
b. N₂O₃
c. NO₂
d. NO
e. N2₂O

asked
User Bob Harner
by
8.8k points

1 Answer

2 votes

M\ N_2=28g/mol\\ 63,8\%--28g\\ 100\%--x\\ x=43,89g

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g

answered
User Saeid Mirzaei
by
7.6k points
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