Question

The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadratic equation in standard form for the equation that would represent the area of the rectangle. Let x equal the length of the rectangle.

Answer 1

the possible answers are, x^2 + 7x - 170 = 0, x^2 + 7x - 170 = y, y=x^2 + 7x - 170, 0=x^2 + 7x - 170 and x^2 + 7x - 170.

Explanation:

I just took the algebra nation

Answer 2

The quadratic equation in standard form for the equation that would represent the area of the rectangle is x^2 + 7c - 170 = 0. The area (A) of the rectangle with length, x, and width, y, is: A = x * y. The width of a rectangle is 7 meters greater than its length: y = 7 + l. The area of the rectangle is 170 square meters: A = 170. Substitute A and y in the formula A = x * y. 170 = x * (7 + x). 170 = 7x + x^2. The standard form of the quadratic equation is ax^2 + bx + c = 0. Therefore, 170 = 7x + x^2 in the standard form is: x^2 + 7c - 170 = 0.