Question

Solve 8m² + 20m = 12 for m by factoring


Please show all work

Answer 1

`8m^(2)+20m=12 / :2`

`4m^(2)+10m=6`

`4m^(2)+10m-6 =0`

`\Delta=b^(2)-4ac`

`\Delta=100-(4*4*-6)`

`\Delta=100+96=196`

`x1=(-b-√(\Delta))/(8)`

`x1=(-10-14)/(8)`

`x1=(-24)/(8)`

`x1=-3`

`x1=(-b+√(\Delta))/(8)`

`x2=(-10+14)/(8)`

`x2=(1)/(2)`

so you can write
`8m^(2)+20m=12 / :2` as


`8(m+3)(m-(1)/(2))=8*[m^(2)+2.5m-1.5]=0`