asked 228k views
0 votes
find the length and width of a rectangular lot with a perimeter of 68m if the length is 6m more than the width

1 Answer

4 votes

l=w+6

P=2(l+w)=68

P=2((w+6)+w)=2(2w+6)=4w+12=68

4w=56 \\ w=14

l=w+6=14+6=20
answered
User Benjamin Clanet
by
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