Question

Identify the turning point of the function f(x)= x^2-2x+8 by writing its equation in vertex form.

Answer 1

The turning point of a quadratic function is its vertex.


`f(x)=x^2-2x+8\\ f(x)=x^2-2x+1+7\\ f(x)=(x-1)^2+7`

So the turning point of the above function is
`(1,7)`