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Solve with completing the square method: 6x²-7x+2=0 and ax²+bx+c=0

Solve with completing the square method: 6x²-7x+2=0 and ax²+bx+c=0
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1 vote
Solve with completing the square method:
6x²-7x+2=0 and  ax²+bx+c=0

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User KevinKirkpatrick
by
7.6k points

1 Answer

5 votes

6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^(2)-4ac = (-7)^(2)-4*6*2=49-48=1 \\ \\x_(1)=(-b-√(\Delta ))/(2a) =(7-√(1))/(2*6)=(7-1)/(12) =(6)/(12)= (1)/( 2)\\ \\x_(2)=(-b+√(\Delta ))/(2a) =(7+√(1))/(2*6)=(7+1)/(12) =(8)/(12)= (2)/( 3)


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User Anad
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