Register

What is x^2+8x-5 in vertex form? Please explain.

What is x^2+8x-5 in vertex form? Please explain.
asked 204k views
5 votes
What is x^2+8x-5 in vertex form? Please explain.

asked
User Feathj
by
7.8k points

2 Answers

5 votes

x^2+8x-5=\\ x^2-8x+16-21=\\ (x-4)^2-21
answered
User Charles Harris
by
8.6k points
4 votes

x^2+8x-5=\\ x^2+2\cdot4\cdot x-5=\\ x^2+2\cdot4\cdot x+4^2-4^2-5=\\ (x+4)^2-16-5=\\ (x+4)^2-21
answered
User Maher Abuthraa
by
8.3k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!