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The circle below is centered at (-3, 2) and has a radius of 3. What is its equation? A. (x-3)2 +(- 2)2 = 9 B. (x+3)2 + (y-2)2 = 3 C. (x+3)2 + (y-2)2 = 9 D. (x-3)2 + (y-2)2 = 3

The circle below is centered at (-3, 2) and has a radius of 3. What is its equation? A. (x-3)2 +(- 2)2 = 9 B. (x+3)2 + (y-2)2 = 3 C. (x+3)2 + (y-2)2 = 9 D. (x-3)2 + (y-2)2 = 3
asked 150k views
8 votes
The circle below is centered at (-3, 2) and has a radius of 3. What is its

equation?
A. (x-3)2 +(- 2)2 = 9
B. (x+3)2 + (y-2)2 = 3
C. (x+3)2 + (y-2)2 = 9
D. (x-3)2 + (y-2)2 = 3

The circle below is centered at (-3, 2) and has a radius of 3. What is its equation-example-1
asked
User Magix
by
7.5k points

1 Answer

5 votes

Answer:

C

Explanation:

The equation is (x-a)^2 + (y-b)^2 = r^2

(x+3)^2+(y-2)^2 = 9

answered
User Alex Fedulov
by
7.9k points
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