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Solve the system by substitution x+5y=4 2x+10y=8
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Solve the system by substitution x+5y=4 2x+10y=8
asked
Jan 23, 2016
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Solve the system by substitution
x+5y=4
2x+10y=8
Mathematics
middle-school
Danbruegge
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Danbruegge
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Multiply the first equation by 2, that gives you the second.
Any x,y
works.
Arussinov
answered
Jan 25, 2016
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Arussinov
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3
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x+5y=4
2x+10y=8
x=
-5y+4
2(-5y+4) +10y=8 substituted in the equation for x
-10y+8+10y=8 distributed
8=8 combined like terms (-10y+10y)
0=0
MANY SOLUTIONS/INFINITE
DDan
answered
Jan 28, 2016
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DDan
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