asked 53.0k views
0 votes
What are the zeros of -3x^2+10x+12

asked
User Alucard
by
7.8k points

1 Answer

4 votes

-3x^2+10x+12=0\\ \Delta=10^2-4\cdot(-3)\cdot12=100+144=244\\ √(\Delta)=√(244)=2√(61)\\ x_1=(-10-2√(61))/(2\cdot(-3))=(-10-2√(61))/(-6)=(5+√(61))/(3)\\ x_2=(-10+2√(61))/(2\cdot(-3))=(-10+2√(61))/(-6)=(5-√(61))/(3)\\
answered
User Thisisnabi
by
7.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.