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9^x=27^(x+2) how do I do that? I don't get how to do it with different bases

9^x=27^(x+2) how do I do that? I don't get how to do it with different bases
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9^x=27^(x+2)
how do I do that? I don't get how to do it with different bases

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User Dani Van Der Meer
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1 Answer

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9^x=27^(x+2)\\ 3^(2x)=3^(3(x+2))\\ 2x=3(x+2)\\ 2x=3x+6\\ 3x-2x=-6\\ x=-6
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User Mike Summers
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