Question

What is a simplified form of -(14x)^0y^-7z

Answer 1

Anything to the power of 0 is one.

Therefore we have:

(1)(y^-7z)

Which simplifies to:

y^-7z

Answer 2

`(1)/(y^(7z))`

Explanation:

Given the expression:

`-(14)^0 \cdot y^(-7z)`

We know that:

`a^0 =1`

`a^(-1) = (1)/(a)`

then;

`1 \cdot y^(-7z)`

⇒
`y^(-7z)`

⇒
`(1)/(y^(7z))`

Therefore, the simplified form of
`-(14)^0 \cdot y^(-7z)` is,
`(1)/(y^(7z))`.