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What is the derivative of y= (x^2+4x+6)^5?

What is the derivative of y= (x^2+4x+6)^5?
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What is the derivative of y= (x^2+4x+6)^5?

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User Anana
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1 Answer

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y= (x^2+4x+6)^5\\ y'=5(x^2+4x+6)^4\cdot(2x+4)\\ y'=10(x+2)(x^2+4x+6)^4
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User Kokila
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