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X2+10x+24=(x+a)(x+a) B is An Interger Find Algebracally All Possible Values of. B

X2+10x+24=(x+a)(x+a) B is An Interger Find Algebracally All Possible Values of. B
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X2+10x+24=(x+a)(x+a) B is An Interger Find Algebracally All Possible Values of. B

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User Agi Hammerthief
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1 Answer

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(x+a)(x+a)=x^2+2ax+a^2\\\\ 2a=10 \wedge a^2=24\\ a=5 \wedge (a=√(24) \vee a=-√(24))\\ a=5 \wedge (a=2√(6) \vee a=-2√(6))

The above is contradiction, so there are no such values of 'a'.
answered
User Adam Shamsudeen
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