Question

How do you find the roots for this following quadratic equation?
x²+9=0

Answer 1

`x^2+9=0\\ x^2=-9\\ x=√(-9) \vee x=-√(-9)\\ x=√(-1\cdot9) \vee x=-√(-1\cdot9)\\ x=√(-1)\cdot\sqrt9 \vee x=-√(-1)\cdot \sqrt9\\ x=i\cdot3 \vee -i\cdot3\\ x=3i \vee x=-3i`