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5 votes
Does the equation sin2(x) – 4 = 0 have any solutions? Explain.

asked
User HaleFx
by
8.6k points

2 Answers

0 votes

Answer:

No, the given equation:


\sin^2x-4=0

does not have any solution.

Explanation:


sin^2x-4=0\\\\this\ means\ that\\\\(sinx-2)(sinx+2)=0\\\\so\ either\ sinx-2=0 or\ sinx+2=0\\\\i.e. sinx=2 or\ sinx=-2\\\\but\ this\ is\ not\ true\ as\ value\ of\ sinx\ lies\ between\ -1\ and\ 1

Hence, the given equation:


\sin^2x-4=0 does not have any solution.

5 votes
Isolate sin(x) by adding 4 and taking the square root of both sides.
State that sin(x) = 2 or sin(x) = –2.State that –2 and 2 are undefined values of the inverse sine function.There are no solutions because –2 and 2 are not in the domain of the function.
answered
User Doodeec
by
7.7k points

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