asked 77.6k views
5 votes
Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

12.0 M * 0.500 l = 6.0 M * V2



12.0 M * 6.0 M = 0.500 l * V2



12.0 M * V1 = 6.0 M * 0.500 l



6.0 M * V1 = 12.0 M * 0.500 l



(12.0 M + 6.0 M) = 0.500 l * V2

asked
User Gabr
by
7.9k points

1 Answer

2 votes
The correct answer is C. The formula for calculating concentration of acid and base is : CAVA = CBVB. Where, CA and VA stand for concentration and volume of acid respectively while CBVB represent concentration and volume of base.
Using the values given in the above equation, we have:
CA =12.0 M. VA =?. CB = 6.0 M. VB = 0.500 Litre.
Using the acid - base equation, we have:
12.0 M* VA = 6.0 M * 0.500.
Thus, option C is the correct answer.
answered
User PedroA
by
8.7k points
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