Point O is the center of the circle in the diagram. What is m∠BCA ? A80° B75° C70° D65°

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asked Aug 22, 2017 227k views

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Mohammad Nikdouz · Answer 1 · 2017-08-26T13:19:20+0000

m ∠ BOA = 360° - 250° = 110°
The sum of all interior angles of the quadrilateral AOBC is 360°
m ∠ BCA = 360° - ( 110° + 90° + 90° ) = 360° - 290° = 70°
Answer: C ) 70°

Point O is the center of the circle in the diagram. What is m∠BCA ? A80° B75° C70° D65°

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